D-d x-cos-x-cos-x-4 -x sin-xB- sin-x-4 -x cos-xC- -sin-x-4 -x cos-xD- -x-4 -x cos-x

The correct option is C d/dx(√(x))=1/2√(x) using this follow chain rule ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Solving Inequalities

d/d x√cos√x=c...

Question

$\frac{d}{d x} (\sqrt{c o s \sqrt{x}}) =$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D

$\frac{d}{d x} (\sqrt{x}) = \frac{1}{2 \sqrt{x}} u s i n g t h i s f o l l o w c h a i n r u l e$

Suggest Corrections

Similar questions

\frac{d}{d x} [\sqrt{sin \sqrt{x}}] =

Q. The integral

\int \frac{s i n^{2} x c o s^{2} x}{(s i n^{5} x + c o s^{3} x s i n^{2} x + s i n^{3} x c o s^{2} x + c o s^{5} x)^{2}} d x

is equal to

\frac{d}{d x} [\sqrt{cos \sqrt{x}}] =

The number of distinct real roots of $∣ ∣ ∣ ∣ \begin{matrix} s i n x & c o s x & c o s x c o s x & s i n x & c o s x c o s x & c o s x & s i n x \end{matrix} ∣ ∣ ∣ ∣ = 0$ in the interval $- \frac{π}{4} \leq x \leq \frac{π}{4}$ is

(a) 0
(b) 2
(c) 1
(d) 3

Q. The number of distinct real roots of

∣ ∣ ∣ ∣ \begin{matrix} sin x & cos x & cos x cos x & sin x & cos x cos x & cos x & sin x \end{matrix} ∣ ∣ ∣ ∣ = 0

in the interval

- \frac{π}{4} \leq x \leq \frac{π}{4}

Join BYJU'S Learning Program

ddx(√cos√x)=

The correct option is D ddx(√x)=12√x using this follow chain rule

$\frac{d}{d x} (\sqrt{c o s \sqrt{x}}) =$

The correct option is D

$\frac{d}{d x} (\sqrt{x}) = \frac{1}{2 \sqrt{x}} u s i n g t h i s f o l l o w c h a i n r u l e$