The correct option is B 2 √(32) + √(48)/(√(8) + √(12)) = √(16 × 2) + √(16 × 3)/√(4 × 2) + √(4 × 3) = 4 √(2) + 4 √(3)/2 √(2) + 2 √(3) = 4 (√(2) + √(3))/2 (√(2) ...

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Byju's Answer

Standard IX

Mathematics

Division of Numbers with Square Roots

√32+√48/√8+√1...

Question

$\frac{\sqrt{32} + \sqrt{48}}{(\sqrt{8} + \sqrt{12})} = ?$

$\sqrt{2}$

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$2$

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$4$

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$8$

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Solution

The correct option is B
$2$

$\frac{\sqrt{32} + \sqrt{48}}{(\sqrt{8} + \sqrt{12})} = \frac{\sqrt{16 \times 2} + \sqrt{16 \times 3}}{\sqrt{4 \times 2} + \sqrt{4 \times 3}} = \frac{4 \sqrt{2} + 4 \sqrt{3}}{2 \sqrt{2} + 2 \sqrt{3}} = \frac{4 (\sqrt{2} + \sqrt{3})}{2 (\sqrt{2} + \sqrt{3})} = 2$

Suggest Corrections

√32+√48(√8+√12)=?

The correct option is B 2 √32+√48(√8+√12)=√16×2+√16×3√4×2+√4×3=4√2+4√32√2+2√3=4(√2+√3)2(√2+√3)=2

$\frac{\sqrt{32} + \sqrt{48}}{(\sqrt{8} + \sqrt{12})} = ?$

The correct option is B
$2$

$\frac{\sqrt{32} + \sqrt{48}}{(\sqrt{8} + \sqrt{12})} = \frac{\sqrt{16 \times 2} + \sqrt{16 \times 3}}{\sqrt{4 \times 2} + \sqrt{4 \times 3}} = \frac{4 \sqrt{2} + 4 \sqrt{3}}{2 \sqrt{2} + 2 \sqrt{3}} = \frac{4 (\sqrt{2} + \sqrt{3})}{2 (\sqrt{2} + \sqrt{3})} = 2$