Fraction 2x-3-x-1x-3-a-x-1-b-x-3- then a-b-

The correct option is C 2 2x + 3(x + 1)(x 3) = ax + 1 + bx 3 Taking L.C.M. on right hand side, we have the numerator as a(x 3) + b(x + 1) = ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Monotonicity in an Interval

Fraction 2x...

Question

Fraction $\frac{2 x + 3}{(x + 1) (x - 3)} = \frac{a}{x + 1} + \frac{b}{x - 3}$ , then $a + b =$ .

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\frac{x^{2} + 5 x + 1}{(x + 1) (x + 2) (x + 3)} = \frac{A}{x + 1} + \frac{B}{(x + 1) (x + 2)}

+ \frac{C}{(x + 1) (x + 2) (x + 3)},

B

\frac{x^{2} + 5 x + 1}{(x + 1) (x + 2) (x + 3)} = \frac{A}{x + 1} + \frac{B}{(x + 1) (x + 2)} + \frac{C}{(x + 1) (x + 2) (x + 3)}

\frac{x^{2} + 3 x + 5}{(x + 1) (x + 2) (x + 3)} =

\frac{A}{(x + 1)} + \frac{B}{(x + 1) (x + 2)} + \frac{c}{(x + 1) (x + 2) (x + 3)}

\frac{x^{3}}{(2 x - 1) (x + 2) (x - 3)} =

A + \frac{B}{(2 x - 1)} + \frac{C}{(x + 2)} + \frac{D}{(x - 3)}

A =

\frac{x^{2} + x + 1}{(x - 1) (x - 2) (x - 3)} = \frac{A}{x - 1} + \frac{B}{x - 2} + \frac{C}{x - 3}

\Rightarrow A + C =

Join BYJU'S Learning Program