If x2+5x+1(x+1)(x+2)(x+3)=Ax+1+B(x+1)(x+2)+C(x+1)(x+2)(x+3), then B is equal to
A
−5
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B
8
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C
0
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D
−6
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Solution
The correct option is A0 x2+5x+1(x+1)(x+2)(x+3)=A(x+1)+B(x+1)(x+2)+C(x+1)(x+2)(x+3) is (x2+5x+1)=A(x+2)(x+3)+B(x+3)+C f(x)=x2+5x+1f(−3)=C f(−3)=−5 C=−5 and f(−2)=B+C −5=B+C So, B=0