Question

Frequency of a gene of PTC non taster is 0.4 than find out the number of heterogygous PTC taster in a population of 4,000:-

• A. 1440
• B. 1920
• C. 1080
• D. 2520

Answer 1

The correct option is B 1920

p=0.4 therefore q=0.6
Therefore for one of the one heterozygous pair it would be $p\times q=0.4\times 0.6=0.24$
Therefore for 2 heterozygous pairs it would be $0.24\times 2=0.48$ means out of hundred there are 48 heterozygous phenotype
Therefore in a population of 4000 there would total of $(\frac{0.48}{100}\times 4000)=1920.$