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Question

Freundlich equation for adsorption of gases (in amount of g) on a solid (in amount of mg) at constant temperature can be expressed as:

A
logxm=logP+1nlogK
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B
logxm=logK+1nlogP
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C
xmPn
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D
xm=P+1nlogK
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Solution

The correct option is C logxm=logK+1nlogP
Freundlich equation for adsorption of gases (in amount of g) on a solid (in amount of mg) at constant temperature can be expressed as folows:
logxm=logK+1nlogP.

It is obtained from the following expression:

xmP1/n or xm=KP1/n
Taking log on both sides, we get
logxm=logK+1nlogP

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