Question

Freundlich equation for adsorption of gases (in amount of $x$ $g$) on a solid (in amount of $m$ $g$) at constant temperature can be expressed as

• A. $\log \frac{x}{m}=\log p+\frac{1}{n}\log k$
• B. $\log \frac{x}{m}=\log k+\frac{1}{n}\log p$
• C. $\frac{x}{m}\propto p^n$
• D. $\frac{x}{m}=\log p+\frac{1}{n}\log k$

Answer 1

The correct option is B $\log \frac{x}{m}=\log k+\frac{1}{n}\log p$

Freundlich equation for adsorption of gases (in amount of x g) on a solid (in amount of m g) at constant temperature can be expressed as
$\log \frac{x}{m}=\log k+\frac{1}{n}\log p$
It can also be expressed as $\frac{x}{m}\propto p^{1/n}$ or $\frac{x}{m}=k{p}^{1/n}$
$\frac{x}{m}$ represents mass of gas adsorbed per unit mass of adsorbent, P is the equilibrium pressure and k and n are constants that depends on the nature of adsorbate and adsorbent and temperature.