Friedel-Crafts alkylation is expected to proceed through a carbocation intermediate. What would be the alkylation product when benzene reacts with cyclopropyl chloride in the presence of $A l C l_{3}$ ?

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Solution

The correct option is D
Here, $A l C l_{3}$ (anhyd) behaves as lewis acid.
$∴$
act as electrophile and will attack on benzene.
(The reaction goes through electrophilic substitution)
So, the correct option is (b)
Also, due to high angular strain the following conversion takes place
Now,
Hence, option (d) is also correct.

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