From a bag containing 4 white and 5 black balls, Karan draws 3 balls at random. What are the odds against these balls being black?

5/37

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37/11

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11/37

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37/5

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Solution

The correct option is D
37/5

Probability of all three balls being black = $\frac{5}{42}$
Probability that three balls are not black =1- $\frac{5}{42}$ = $\frac{37}{42}$
Hence, odds against these balls being black = $\frac{37}{42}$ : $\frac{5}{42}$

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From a bag containing 4 white and 5 black balls, Karan draws 3 balls at random. What are the odds against these balls being black?

The correct option is D 37/5 Probability of all three balls being black = 542 Probability that three balls are not black =1-542= 3742 Hence, odds against these balls being black = 3742:542

The correct option is D
37/5

Probability of all three balls being black = $\frac{5}{42}$
Probability that three balls are not black =1- $\frac{5}{42}$ = $\frac{37}{42}$
Hence, odds against these balls being black = $\frac{37}{42}$ : $\frac{5}{42}$