From a balloon rising vertically upwards at $5 m / s$ a stone is thrown up at $10 m / s$ relative to the balloon. Its velocity with respect to ground after $2 s$ is (Take $g = 10 m / s^{2}$ )

0 m / s

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20 m / s

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10 m / s

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5 m / s

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Solution

The correct option is D $5 m / s$
The $i n i t i a l$ velocity with respect to $g r o u n d$ will be $10 + 5 = 15 m / s$
after $2 s e c$ its velocity will be $v = 15 - g t = 15 - 10 \times 2 = - 5 m / s$
Whose value is $5 m / s$
Note- Once the stone is projected from balloon it will not have any impact of the balloon after that moment.
Option D is correct.

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From a balloon rising vertically upwards at 5 m/s a stone is thrown up at 10 m/s relative to the balloon. Its velocity with respect to ground after 2 s is (Take g=10m/s2)

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