Question

From a pack of cards, two are drawn, the first being replaced before the second is drawn. Find the probability that the first is a club and the second is a red card.

• A. $\frac{1}{52}$
• B. $\frac{1}{26}$
• C. $\frac{1}{8}$
• D. $\frac{4}{13}$

Answer 1

The correct option is C $\frac{1}{8}$

Total number of cards$=52$

Total number of clubs$=13$

$\therefore$ P(club)$=\frac{13}{52}=\frac{1}{4}$

Total number of red cards $=26$

$\therefore$P(red)$=\frac{26}{52}=\frac{1}{2}$

$\therefore$P(club and red card)$=\frac{1}{4}\times \frac{1}{2}=\frac{1}{8}$.