From a rectangular sheet of 20 m x 10 m, 4 squares of side 2.5 m are cut out from the corners and made into a box. Find the TSA of the open cuboid so formed.

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Solution

A square of side 2.5 m is cut off from all the corners.
Therefore the length of a rectangular sheet changes to 15 m [20 - (2 x 2.5)] and breadth to 5 m [10 - (2 x 2.5)].

Therefore,
Surface area of the resulting figure
= sum of areas of I, II, III, IV, V

= (15 x 2.5) + (5 x 2.5) + (15 x 2.5) + (5 x 2.5) + (15 x 5)
= 175 $m^{2}$ .

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