From a set of 17 cards, numbered 1, 2, ..., 17, one is drawn. What is the probability that the number is multiple of 3 or 7?

5/17

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7/17

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8/17

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6/17

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Solution

The correct option is C $\frac{7}{17}$

The total number of possible outcomes is $17$

The number of favourable outcomes is $3, 6, 7, 9, 12, 14$ and $15$

$= 7$

Thus, the required probability = $\frac{number of favourable outcomes}{total number of outcomes}$

= $\frac{7}{17}$ .

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From a set of 17 cards, numbered 1, 2, ..., 17, one is drawn. What is the probability that the number is multiple of 3 or 7?

The correct option is C 717The total number of possible outcomes is 17 The number of favourable outcomes is 3,6,7,9,12,14 and 15 =7 Thus, the required probability = number of favourable outcomestotal number of outcomes = 717.

The correct option is C $\frac{7}{17}$

The total number of possible outcomes is $17$

The number of favourable outcomes is $3, 6, 7, 9, 12, 14$ and $15$

$= 7$

Thus, the required probability = $\frac{number of favourable outcomes}{total number of outcomes}$

= $\frac{7}{17}$ .