Question

From a solid cylinder whose height is $8cm$ and radius $6cm$, a conical cavity of height $8cm$ and of base radius $6cm$ is hollowed out. Find the volume of the remaining solid. Also, find the total surface area of the remaining solid. [Take $\pi =3.14$.]

Answer 1

Radius of cylinder $=$ Radius of cone $=6cm$

Height of cylinder $=$ Height of cone $=8cm$

Volume of the solid cylinder $=3.14\times 6^2\times 8$

$=3.14\times 36\times 8$

$=904.32c{m}^3$

Volume of the conical cavity =

$=\frac{3.14\times 6^2\times 8}{3}$

$=3.14\times 12\times 8$

$=301.44c{m}^3$

Volume of resulting solid = Volume of cylinder- Volume of conical cavity.

$=904.32-301.44=602.88c{m}^3$