Question

From a solid cylinder whose height is 8 cm and radius is 6 cm, a conical cavity of height 8 cm and base radius 6 cm is hollowed out. Find the volume of remaining solid. $(Use\pi =\frac{22}{7})$ [4 MARKS]

Answer 1

ormula: 1 Mark
Application: 1 Mark
Solution: 2 Marks

Volume of remaining solid= Volume of cylinder - Volume of cone
$=\pi R^{2}h-\frac{1}{3}\pi r^{2}h=\pi h(R^2-=\frac{r^2}{3})$
[$\because$ Height of cylinder and cone are equal, i.e. ic m]\\
$=\frac{22}{7}\times 8\times (36-\frac{36}{3})=\frac{22}{7}\times 8\times (36-12)=603.43c{m}^3(approx.)$