Question

From a solid cylinder whose height is $8cm$ and radius is $6cm$, a conical cavity of height $8cm$ and of base radius $6cm$ is hollowed out. Find the volume of the remaining solid correct to $4$ places of decimals.
$(\pi =3.1416)$

Answer 1

Volume of remaining solid $=$ Volume of cylinder $-$ Volume of conical cavity

$\Rightarrow {\pi r}^{2}H-\frac{1}{3}\pi r^{2}H=\frac{2}{3}{\pi r}^{2}H=\frac{2}{3}\times 3.146\times 6\times 6\times 8$

$=603.1872{cm}^3$