Question

From a solid cylinder whose height is 8 cm and radius is 6 cm a conical cavity of height 8 cm and base radius 6 cm is hollowed out Find the volume of the remaining solid

• A. $603c{m}^3$
• B. $720c{m}^3$
• C. $548c{m}^3$
• D. $637c{m}^3$

Answer 1

The correct option is A $603c{m}^3$

GIven h=8 cm r=6 cm
$V_{cylinder}=\pi r^{2}h$
$V_{cone}=\frac{1}{3}\pi r^{2}h$
$V_{solid}=V_{cylinder}-V_{cone}$
$=\pi r^{2}h(1-\frac{1}{3})$
$=\frac{2}{3}\pi r^{2}h$
$=\frac{2}{3}\times \frac{22}{7}\times 6\times 8$
$=603c{m}^2$
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