Question

From a solid right circular cylinder with height 10 cm and radius of the base 6 cm, a right circular cone of the same height and same base is removed. Find the volume of the remaining solid.

Answer 1

Remaining volume of solid=volume of cylinder-volume of cone
=$\pi r^{2}h-\frac{1}{3}\pi r^{2}h$
=$\frac{2}{3}\pi r^{2}h$
=$\frac{2}{3}\times \frac{22}{7}\times 6\times 6\times 10$
=$753.6c{m}^3$