Question

From a supply of identical capacitors rated $8\mu F,250V$ the minimum number of capacitors required to form a composite of $16\mu F,1000V$ is

• A. 2
• B. 4
• C. 16
• D. 32

Answer 1

The correct option is D 32

The number of capacitance to be connected in series $n=\frac{voltageratingrequired}{voltageratingofacapacitorgiven}=\frac{1000}{250}=4$
Equivalent capacitance, $C_{eq}=(\frac{1}{8}+\frac{1}{8}+\frac{1}{8}+\frac{1}{8}{)}^{-1}=(\frac{4}{8}{)}^{-1}=2$
Number of rows required $=\frac{capacitancerequired}{capacitanceofeachrow}=\frac{16}{2}$
Thus the minimum number of capacitors to be required $=4\times 8=32$