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1st Equation of Motion

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Question

From a top of a tower 20m high, a ball is thrown horizontally .if the line joining the point of projection to the point where it hits the ground makes an angle of 45 with the horizontal ,then the initial velocity of ball is

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Solution

Dear Student ,

Since it is projectile motion .
$U_{x} = U i n t i a l v e l o c i t y o f b a l l U_{y} = 0 a s b a l l i s t h r o w n h o r i z o n t a l l y i n t i a l v e l o c i t y i n y d i r e c t i o n w i l l b e z e r o . d i s p l a c e m e n t i n X d i r e c t i o n S_{x} = 20 m a s a n g l e i s 45 d e g r e e . t i m e t a k e n t o h i t g r o u n d t = 20 / U . Y c o m p o n e n t o f v e l o c i t y a f t e r t s e c o n d w i l l b e e q u a l t o U a s i t m a k e 45 d e g r e e a n g l e w i t h h o r i z o n t a l . V_{Y} = 10 \times 20 / U U = \frac{200}{U} U^{2} = 200 U = 10 \sqrt{2} m / s R e g a r d s$

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