Question

From $B_2{H}_6$, the following can be prepared, except for:

• A. $H_{3}B{O}_3$
• B. $B_2(C{H}_3{)}_4{H}_2$
• C. $B_2(C{H}_3{)}_6$
• D. $NaB{H}_4$

Answer 1

The correct option is C $B_2(C{H}_3{)}_6$

Only four of the six hydrogens from $B_2{H}_6$ can be substituted by $C{H}_3$ groups. So $B_2(C{H}_3{)}_6$ cannot be prepared from diborane.
$B_2{H}_6+6H_{2}O\to 2H_{3}B{O}_3+6H_2$
$B_2{H}_6+2NaH\to 2NaB{H}_4$