From the $B_{2} H_{6}$ , all the following can be prepared except:

H_{3} B O_{3}

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[B H_{2} (N H_{3})_{2}]^{+} [B H_{4}]^{-}

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B_{2} (C H_{3})_{6}

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N a B H_{4}

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Solution

The correct option is C $B_{2} (C H_{3})_{6}$
$B_{2} H_{6} + 6 H_{2} O \to 2 B {(O H)}_{3} + 6 H_{2} B_{2} H_{6} + 2 N H_{3} \to [{B H}_{2} {({N H}_{3})}_{2}]^{+} [{B H}_{4}]^{-} {2 B}_{2} H_{6} + 2 N a \to {N a B H}_{4} + N a B_{3} H_{8}$

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