From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in the given figure. Find the area of the remaining portion of the square.

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Solution

Each quadrant is a sector of 90° in a circle of 1 cm radius.

Area of each quadrant

Area of square = (Side)² = (4)² = 16 cm²

Area of circle = πr² = π (1)²

Area of the shaded region = Area of square − Area of circle − 4 × Area of quadrant

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From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in the given figure. Find the area of the remaining portion of the square.

Each quadrant is a sector of 90° in a circle of 1 cm radius. Area of each quadrant Area of square = (Side)2 = (4)2 = 16 cm2 Area of circle = πr2 = π (1)2 Area of the shaded region = Area of square − Area of circle − 4 × Area of quadrant

Each quadrant is a sector of 90° in a circle of 1 cm radius.

Area of each quadrant

Area of square = (Side)² = (4)² = 16 cm²

Area of circle = πr² = π (1)²

Area of the shaded region = Area of square − Area of circle − 4 × Area of quadrant