From Metro Station A a train starts at regular interval of 10mins and runs towards B Metro Station with constant speed of 80kmph without stopping. At some point of time, all the trains simultaneously have to reduce their speed 50kmph due to defect in rails. What will become the time intervals between arrivals of the trains at the Metro Station B during the defect in rails?

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Solution

The distance between the successive trains on the track is
= 10 min * 80 kmph
=(10*80)/60 km
=40/3 km

When the speed of all trains is reduced to 50 kmph, then this
distance is covered in (40/3) km / 50 kmph = 4/15 hr = 16 minutes

time intervals = 15 minutes

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The distance between the successive trains on the track is = 10 min * 80 kmph =(10*80)/60 km =40/3 km When the speed of all trains is reduced to 50 kmph, then this distance is covered in (40/3) km / 50 kmph = 4/15 hr = 16 minutes time intervals = 15 minutes

The distance between the successive trains on the track is
= 10 min * 80 kmph
=(10*80)/60 km
=40/3 km

When the speed of all trains is reduced to 50 kmph, then this
distance is covered in (40/3) km / 50 kmph = 4/15 hr = 16 minutes

time intervals = 15 minutes