Question

From the displacement time graph of a particle executing SHM, find the maximum velocity of the particle.

• A. $2{\text{ms}}^{-1}$
• B. $\pi {\text{ms}}^{-1}$
• C. $2\pi {\text{ms}}^{-1}$
• D. $\frac{\pi }{2}{\text{ms}}^{-1}$

Answer 1

The correct option is C $2\pi {\text{ms}}^{-1}$

We know that, maximum velocity of particle executing SHM
$v_{\text{max}}=A\omega$

Here, $A=0.2\text{m}$, $\omega =\frac{2\pi }{T}=\frac{2\pi }{0.2}$
$\Rightarrow v_{\text{max}}=0.2\left(\frac{2\pi }{0.2}\right)=2\pi {\text{ms}}^{-1}$