From the following data- the heat of formation of Ca OH 2 s at 18 0 C- is-Kcal-i CaO s - H 2 O - -Ca OH 2 s - H 18 0 C-15-26 Kcal-ii H 2 O - - H 2 g -1-2 O 2 g - H 18 0 C-68-37 Kcal-iii Ca s -1-2 O 2 g -CaO s - H 18 0 C-151-80 Kcal-

The correct option is A 235.43We have to calculate formation Ca+H_2+O_2→ Ca(OH)_2 ......(1) CaO+H_2O→ Ca(OH)_2 #160; #160; #160; #160; ...

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Heat of Formation

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Question

From the following data, the heat of formation of $C a {(O H)}_{2} (s)$ at $18^{0} C$ . is....Kcal.
(i) $C a O (s) + H_{2} O (ℓ) = C a {(O H)}_{2} (s); △ H_{18^{0}} C = - 15.26 K c a l . . . .$
(ii) $H_{2} O (ℓ) = H_{2} (g) + 1 / 2 O_{2} (g); △ H_{18^{0}} C = 68.37 K c a l . . . .$
(iii) $C a (s) + 1 / 2 O_{2} (g) = C a O (s); △ H_{18^{0}} C = - 151.80 K c a l . . . .$

-98.69

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-235.43

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194.91

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98.69

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C a (O H)_{2} (s)

18^{\circ} C

K c a l

C a O (s) + H_{2} O (l) = C a (O H)_{2} (s); △ H_{18^{\circ}} C = - 15.26 K c a l . . . . .

H_{2} O (l) = H_{2} (g) + \frac{1}{2} O_{2} (g); △ H_{18^{\circ}} C = 68.37 K c a l . . . . .

C a (s) + \frac{1}{2} O_{2} (g) = C a O (s); △ H_{18^{\circ}} C = - 151.80 K c a l . . . . .

C a O (s) + H_{2} O (l) = C a (O H)_{2} (s)

Δ H_{180^{o} C} = - 15.26 k c a l

H_{2} O (l) = H_{2} (g) + \frac{1}{2} O_{2} (g)

Δ H_{180^{o} C} = 68.37 k c a l

C a (s) + \frac{1}{2} O_{2} (g) = C a O (s)

Δ H_{180^{o} C} = - 151.80 k c a l

C a (O H)_{2} (s)

18^{\circ} C

C H_{3} C O O H (l)

25^{\circ} C

C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} + 2 H_{2} O (l); Δ H = - 208.34

C (s) + O_{2} (g) \to C O_{2} (g); Δ H = - 94.05

H_{2} (g) + \frac{1}{2} O_{2} \to H_{2} O (l); Δ H = - 68.32

2 C (s) + 2 O_{2} (g) ⟶ 2 C O_{2} (g); Δ H = - 787 k J . . . (i)

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 286 k J . . . (i i)

C_{2} H_{2} (g) + \frac{5}{2} O_{2} (g) ⟶ 2 C O_{2} (g) + 3 H_{2} O (l) . . . . (i i i)

Δ H = - 1301 k J

C H_{3} O H (1) + \frac{3}{2} O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (I); Δ, H^{⊖} = - 726 k J m o l^{- 1}

C (g r a p h i t e) + O_{2} (g) \to C O_{2} (g); Δ_{c} H^{⊖} = - 393 k J m o l^{- 1}

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (I); Δ_{f} H^{⊖} = - 286 k J m o l^{- 1}

{C H}_{3} O H (l)

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