From the following data- the heat of formation of CaOH2s at 18-C is - Kcal-i CaOs - H2O l - CaOH2s- H18-C - -15-26 Kcal -ii H2Ol - H2g - 12O2g- H18-C - 68-37 Kcal -iii Cas -12 O2g - CaOs- H18-C - -151-80 Kcal -

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Heat of Formation

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Question

From the following data, the heat of formation of $C a (O H)_{2} (s)$ at $18^{\circ} C$ is .... $K c a l$ .
(i) $C a O (s) + H_{2} O (l) = C a (O H)_{2} (s); △ H_{18^{\circ}} C = - 15.26 K c a l . . . . .$
(ii) $H_{2} O (l) = H_{2} (g) + \frac{1}{2} O_{2} (g); △ H_{18^{\circ}} C = 68.37 K c a l . . . . .$
(iii) $C a (s) + \frac{1}{2} O_{2} (g) = C a O (s); △ H_{18^{\circ}} C = - 151.80 K c a l . . . . .$

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C a O (s) + H_{2} O (l) = C a (O H)_{2} (s)

Δ H_{180^{o} C} = - 15.26 k c a l

H_{2} O (l) = H_{2} (g) + \frac{1}{2} O_{2} (g)

Δ H_{180^{o} C} = 68.37 k c a l

C a (s) + \frac{1}{2} O_{2} (g) = C a O (s)

Δ H_{180^{o} C} = - 151.80 k c a l

C a (O H)_{2} (s)

18^{\circ} C

C a {(O H)}_{2} (s)

18^{0} C

C a O (s) + H_{2} O (ℓ) = C a {(O H)}_{2} (s); △ H_{18^{0}} C = - 15.26 K c a l . . . .

H_{2} O (ℓ) = H_{2} (g) + 1 / 2 O_{2} (g); △ H_{18^{0}} C = 68.37 K c a l . . . .

C a (s) + 1 / 2 O_{2} (g) = C a O (s); △ H_{18^{0}} C = - 151.80 K c a l . . . .

C H_{3} C O O H (l)

25^{\circ} C

C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} + 2 H_{2} O (l); Δ H = - 208.34

C (s) + O_{2} (g) \to C O_{2} (g); Δ H = - 94.05

H_{2} (g) + \frac{1}{2} O_{2} \to H_{2} O (l); Δ H = - 68.32

25^{o}

H_{2 (g)} + \frac{1}{2} O_{2 (g)} \to H_{2} O (l)

H^{+} (a q) + O H^{-} (a q) = H_{2} O (l); Δ H = - X_{1} k J . m o l^{- 1}

H_{2} (g) + \frac{1}{2} O_{2} (g) = H_{2} O (l); Δ H = - X_{2} k J . m o l^{- 1}

C O_{2} (g) + H_{2} (g) = C O (g) + H_{2} O (l); Δ H = + X_{3} k J . m o l^{- 1}

C_{2} H_{2} (g) + \frac{5}{2} O_{2} (g) = 2 C O (g) + H_{2} O (l); Δ H = + X_{4} k J . m o l^{- 1}

H_{2} O (l)

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