From the following equations, pick out the possible nuclear fusion reaction

$_{6} C^{13} +_{1} H^{1} ⟶_{6} C^{14} + 4.3 M e V$

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_{6} C^{12} +_{1} H^{1} ⟶_{7} N^{13} + 2 M e V

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_{7} N^{14} +_{1} H^{1} ⟶_{8} O^{16} + 7.3 M e V

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_{92} U^{235} +_{0} n^{1} ⟶_{54} X e^{140} +_{38} S r^{94} + 2 (_{0} n^{1}) + γ + 200 M e V

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Solution

The correct option is B $_{6} C^{12} +_{1} H^{1} ⟶_{7} N^{13} + 2 M e V$
Atomic no. and mass no. are conserved only in (b) and (d). (d) is a nuclear fission reaction. Therefore, (b) is the answer

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Similar questions

_{7} N^{14} +_{0} n^{1} \to_{6} C^{14} +_{1} H^{1}

_{3} L i^{7} +_{1} H^{1} \to 2_{2} H e^{4} + 17.25 M e V

_{1} H^{2} +

_{1} H^{3}

⟶

_{0} n^{1} +

_{2} H e^{4} .

1_{H}^{1}

_{7} N^{14} +_{1} H^{1} \to_{8} O^{15} + X

_{6} C^{12}

7.68

_{6} C^{13}

7.47

_{6} C^{13}

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