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Question

From the following figure. find:
(secx0tanx0)(secx0+tanx0)

186554.jpg

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Solution

Let the given triangle be ABC, where ABC=90, AB=1,BC=y,AC=2
By Pythagoras Theorem,
AC2=AB2+BC2
22=12+y2
y2=3
y=3
Now, (secx0tanx0)(secx0+tanx0)
= sec2xtan2x
= (HB)2(PB)2
= 2131
= 43
= 1

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