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Question

From the following frequency distribution, find the median class:

Cost of living index14001550155017001700185018502000Number of weeks815218

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Solution

Cost of living indexNo. of weeks (f)c.f.140015508815501700152317001850214418502000852 f=n=52
Here, n=52
n2=522=26
The cumulative frequency greater than or equal to 26 is 44 Or 26th term lies in the class interval 17001850.
Median class is 17001850.


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