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Intensity vs Photocurrent

From the foll...

Question

From the following graph of photo current against collector plate potential, for two different intensities of light $I_{1}$ and $I_{2}$ , one can conclude

I_{1} = I_{2}

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I_{1} > I_{2}

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I_{1} < I_{2}

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Comparison is not possible

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Solution

The correct option is C $I_{1} < I_{2}$
Best Answer: Photocurrent is directly proportional to intensity for a fixed frequency of the incident light. hence $I_{2} > I_{1}$

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