From the following sequence calculate the lattice energy of AB(s): A(s)→A(g)+e; 610kJmol−1 B(g)+e→B(g);−260kJmol−1 A(s)+B(g)→AB(s);−569kJmol−1
A
−219
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B
−919
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C
+1539
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D
+301
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Solution
The correct option is B−919
The lattice energy of a crystalline solid is usually defined as the energy of formation of the crystal from infinitely-separated ions, molecules, or atoms.
let the equations be 1, 2 and 3.
We will get the lattice energy by 3−2−1= −569+260−610=−919