Question

From the following $V-T$ diagrams we can conclude

• A. $P_1=P_2$
• B. $P_1>P_2$
• C. $P_1<P_2$
• D. $Noneofthese$

Answer 1

Answer: (C)

$P_1<P_2$

Given: V-T graph

Solution:

The V-T graph is a straight line with some y-intercept.

Let the equation of straight line be V=mT+A where m is the slope of the line and A is the y intercept ( both m,A>0).

$PV=nRT$

Putting the value of V in the above equation, we get,

$P=\frac{nRT}{mT+A}$

$\Rightarrow P=\frac{nR}{m+\left(\frac{A}{T}\right)}$

As, $T_2>T_1$

$\Rightarrow \frac{A}{T_1}>\frac{A}{T_2}$

$\therefore P_2>P_1$

Hence the correct option is C.