Question

From the given figure find the value of $\sqrt{2}x$, if :

Answer 1

Consider triangle ABC, $\angle ABC={90}^{\circ }$, $AB=20$ and $\angle ACB={45}^{\circ }$
Now, $\sin 45=\frac{P}{H}$
$\frac{1}{\sqrt{2}}=\frac{20}{x}$
$x=20\sqrt{2}$
$x=28.28$