From the p - T graph what conclusion can be drawn?

V_{2} = V_{1}

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V_{2} < V_{1}

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V_{2} > V_{1}

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Nothing can be predicted

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Solution

The correct option is C $V_{2} > V_{1}$
Solution:- (C) $V_{2} > V_{1}$
From ideal gas equation,
$P V = n R T$
$\Rightarrow \frac{V}{n R} = \frac{T}{P} = tan θ (Slope)$
$∵ θ_{2} > θ_{1} \Rightarrow V_{2} > V_{1}$

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From the p - T graph what conclusion can be drawn?

The correct option is C V2>V1Solution:- (C) V2>V1From ideal gas equation,PV=nRT⇒VnR=TP=tanθ(Slope)∵θ2>θ1⇒V2>V1

The correct option is C $V_{2} > V_{1}$
Solution:- (C) $V_{2} > V_{1}$
From ideal gas equation,
$P V = n R T$
$\Rightarrow \frac{V}{n R} = \frac{T}{P} = tan θ (Slope)$
$∵ θ_{2} > θ_{1} \Rightarrow V_{2} > V_{1}$