From the sum of $4 + 3 x$ and $5 - 4 x + 2 x^{2}$ , subtract the sum of $3 x^{3} - 5 x$ and $- x^{2} + 2 x + 5$

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Solution

$(5 - 4 x + 2 x^{2}) + (4 + 3 x) = 9 - x + 2 x^{2}$ ....A

$(3 x^{3} - 5 x) + (- x^{2} + 2 x + 5) = 3 x^{3} - x^{2} - 3 x + 5$ ....B

A-B gives

$9 - x + 2 x^{2} - 3 x^{3} + x^{2} + 3 x - 5$

$= - 3 x^{3} + 3 x^{2} + 2 x + 4$

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Similar questions

(4 + 3 x - x^{2})

(5 - 4 x + 2 x^{2})

(3 x^{2} - 5 x)

(- x^{2} + 2 x + 5)

4 + 3 x

5 - 4 x + 2 x^{2}

3 x^{2} - 5 x

- x^{2} + 2 x + 5

4 + 3 x a n d 5 - 4 x + 2 x^{2}

3 x^{2} - 5 x a n d - x^{2} + 2 x + 5

Question 6 (b)

From the sum of $4 + 3 x a n d 5 - 4 x + 2 x^{2}$ , subtract the sum of $3 x^{2} - 5 x a n d - x^{2} + 2 x + 5$ .

4 + 3 x a n d 5 - 4 x + 2 x^{2}

3 x^{2} - 5 x a n d - x^{2} + 2 x + 5

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