From the sum of $5 a^{2} - 3 a + 2$ and $- 8 a^{2} + 5 a + 6$ , subtract $a^{2} + 7 a - 4$

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Solution

Sum of $5 a^{2} - 3 a + 2 + (- 8 a^{2} + 5 a + 6)$

$= 5 a^{2} - 3 a + 2 - 8 a^{2} + 5 a + 6$

Sum $= - 3 a^{2} + 2 a + 8$

Subtract $a^{2} + 7 a - 4$

$= - 3 a^{2} + 2 a + 8 - (a^{2} + 7 a - 4)$

$= - 3 a^{2} + 2 a + 8 - a^{2} - 7 a + 4$

$= - 4 a^{2} - 5 a + 12$

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\frac{sin 3 A + 2 sin 5 A + sin 7 A}{sin A + 2 sin 3 A + sin 5 A} = \frac{sin 5 A}{sin 3 A}

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