From the sum of a2-b3-c4 and 2a3-3b4-4c5- subtract a16-b12-c20

[(a2+b3+c4)+(2a3+3b4+4c5)] (a6+b12+c20) ...

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Addition and Subtraction of Algebraic Expression

From the sum ...

Question

From the sum of $\frac{a}{2} + \frac{b}{3} + \frac{c}{4}$ and $\frac{2 a}{3} + \frac{3 b}{4} + \frac{4 c}{5}$ , subtract $\frac{a}{16} + \frac{b}{12} + \frac{c}{20}$

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3 a - 2 b + 4 c

3 b - 2 c

a - b - c

\frac{a^{2}}{2} + \frac{b^{3}}{3} - \frac{c^{3}}{4}

\frac{{2 a}^{2}}{3} + \frac{{3 b}^{3}}{4} - \frac{{4 c}^{3}}{5}

a^{2} + b^{3} + c^{3}

\frac{a^{2}}{2} + \frac{b^{3}}{3} - \frac{c^{3}}{4}; \frac{2 a^{2}}{3} + \frac{3 b^{3}}{4} - \frac{4 c^{3}}{5}; a^{2} + b^{3} + c^{3}

(2 a - 3 b + 4 c)

(a + 3 b - 4 c), (4 a - b + 9 c)

(- 2 b + 3 c - a)

\frac{a}{2} = \frac{b}{3} = \frac{c}{4} = \frac{2 a - 3 b + 4 c}{p}

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