The given points are G(10, ndash;8) and H( ndash;3, nbsp; ndash;2 ). From these points, nbsp; x1 = 10, y1 = ndash;8, x2 = ndash;3, y2 = ndas ...

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Collinearity Condition

G 10,-8 H -3,...

Question

G (10, -8) H(-3, -2)

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Solution

The given points are G(10, –8) and H(–3, –2 ).
From these points, x₁ = 10, y₁ = –8, x₂ = –3, y₂ = –2.
By the distance formula,

$GH = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(- 3 - 10)^{2} + [- 2 - (- 8)]^{2}} = \sqrt{(- 13)^{2} + (6)^{2}} = \sqrt{169 + 36} = \sqrt{205}$

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