The following equations are balanced atomwise and chargewise. (i) Cr2O27+8H++3H2O2→2Cr3++7H2O+3O2 (ii) Cr2O27+8H++5H2O2→2Cr3++9H2O+4O2 (iii) Cr2O27+8H++7H2O2→2Cr3++11H2O+5O2 The precise equation/equations representing the oxidation of H2O2 is/are :
A
(i) only
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B
(ii) only
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C
(iii) only
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D
all the three
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Solution
The correct option is A (i) only The reactions are as follows: 6e−+14H++Cr2O2−7→2Cr3++7H2O 3H2O2→3O2+6H++6e− Cr2O2−7+8H++3H2O2→2Cr3++7H2O+3O2 Therefore, only (i) is correct.