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Question

g(x)=x4x3+x2+3x5

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Solution

g(x)=x4x3+x2+3x5

Given, x=2+3i

x2=5+12i

x3=46+9i

g(2+3i)=2+3i(4(2+3i)3)+(2+3i)2+3(2+3i)5

=(2+3i)(4(46+9i))+(5+12i)+6+9i5

=(2+3i)(509i)5+12i+6+9i5

=(2+3i)(509i)4+21i

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