Question

Gas A and B are at ${30}^{o}C$ and at ${20}^{o}C$ respectively. Both of them are at 1 atm. Determine the ratio of the volume of 1 mole of gas A to 1 mole of gas B?

• A. 1 : 1
• B. 2 : 3
• C. 3 : 2
• D. 303 : 293
• E. 606 : 293

Answer 1

Answer: (D)

303 : 293

According to Charles's Law,
$\frac{V}{T}=k$
Hence, $\frac{V1}{T1}=\frac{V2}{T2}$
$V1=$ volume of 1 mole of gas A
$V2=$ volume of 1 mole of gas B
$T1={30}^{o}C=30+273=303K$
$T2={20}^{o}C=20+273=293K$
Hence, $\frac{V1}{303}=\frac{V2}{293}$
$\frac{V1}{V2}=\frac{303}{293}$