Question

Gas $X$ burns with blue flame.

$Z\stackrel{H_{2}O}{\to }B$
Gas $Y+B⟶$ milkiness

Mark the correct choice.

• A. $A=CaC{O}_3$, $X=CO$, $Y=C{O}_2$, $Z=CaO$, $B=Ca{\left(OH\right)}_2$
• B. $A=Ca{C}_2{O}_4$, $X=CO$, $Y=C{O}_2$, $Z=CaO$, $B=Ca{\left(OH\right)}_2$
• C. $A=Ca{C}_2{O}_4$, $X=C{O}_2$, $Y=CO$, $Z=CaO$, $B=Ca{\left(OH\right)}_2$
• D. $A=CaOC{l}_2$, $X=C{l}_2$, $Y=O_2$, $Z=CaO$, $B=Ca{\left(OH\right)}_2$

Answer 1

Answer: (B)

$A=Ca{C}_2{O}_4$, $X=CO$, $Y=C{O}_2$, $Z=CaO$, $B=Ca{\left(OH\right)}_2$

When $CaO$ is treated with water then there is formation of lime water which is transparent in color. When this transparent lime water is treated with an excess of $C{O}_2$, then the milkiness produced is due to the formation of the $Ca(HC{O}_3{)}_2$.

$CaO\stackrel{H_{2}O}{\to }Ca(OH{)}_2$

Gas $C{O}_2+Ca(OH{)}_2⟶Ca(HC{O}_3{)}_2$ (milkiness)

Gas $CO$ burns with a blue flame.