ge decrease in the acceleration due to gravity when a body is taken from theFind the percesurface of earth to a height of 64 km from its Surface. \lbrack Take R 6.4 x 106 ml2hHint: Use 9.-9

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Q. Find the percentage decrease in the acceleration due to gravity when a body is taken from the surface of earth to a height of

64 k m

from its surface. [Take

R_{e} = 6.4 \times 10^{6} m]

A body weighs 100 N on the surface of Earth. What will be the acceleration due to gravity acting on the body at a height of 3400 km above Earth's surface? Taking the mass of Earth $= 6 \times 10^{24} k g$ , Radius of earth $= 6.4 \times 10^{6} m$ and $G = 6.7 \times 10^{- 11} N m^{2} k g^{- 2}$ .

At which height from earth surface acceleration due to gravity is decreased by 75% of its value at earth surface?

Q. If

g

is the acceleration due to gravity on the Earth' surface, find the gain in potential energy of a body of mass

m

when taken from the surface of Earth at a height equal to the radius

R

of the Earth.

The acceleration of a body due to the attraction of the earth (radius R) at a distance 2R from the surface of the earth is (g = acceleration due to gravity at the surface of the earth)

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