Question

Ge (II) compounds are powerful reducing agents where as Pb (IV) compounds are strong oxidants.
It can be due to:

• A. Pb is more electropositive than Ge
• B. Ionization potential ofl ead is less than that of Ge
• C. Ionic radii of $P{b}^{2+}$ and $P{b}^{4+}$ are larger than those of $G{e}^{2+}$ and $G{e}^{4+}$
• D. More pronounced inert pair effect in Pb than in Ge

Answer 1

The correct option is D More pronounced inert pair effect in Pb than in Ge

Ge (II) tends to acquire Ge (IV) state by loss of electrons. Hence it is reducing in nature.

Pb (IV) tends to acquire Pb (II) O.S. by gain of electrons. Hence it is oxidising in nature. This is due to inert pair effect.

Hence, option D is correct.