Geeta’s age is 3 years more than thrice m, the age of Meeta. Write an equation of first degree to display this information.

g - 3 = 3m

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g + 3 = 3m

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g - 3m + 3 = 0

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g + 3m + 3 = 0

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Solution

The correct option is A
g - 3 = 3m

g - 3 = 3m

According to question, geeta’s age is more than meeta’s age. So keeping it on one

Side of the equation, we can write g = 3m + 3

Which implies

g - 3 = 3m

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Geeta’s age is 3 years more than thrice m, the age of Meeta. Write an equation of first degree to display this information.

The correct option is A g - 3 = 3mg - 3 = 3m According to question, geeta’s age is more than meeta’s age. So keeping it on one Side of the equation, we can write g = 3m + 3 Which implies g - 3 = 3m

The correct option is A
g - 3 = 3m

g - 3 = 3m

According to question, geeta’s age is more than meeta’s age. So keeping it on one

Side of the equation, we can write g = 3m + 3

Which implies

g - 3 = 3m