General form of a three-digit number abc is

a + b + c

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100×a + 10×b + 1×c

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100×a + 10×b + 10×c

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Solution

The correct option is B 100×a + 10×b + 1×c
abc is a 3-digit number, where:
• a is in the hundreds place
• b is in the tens place
• c is in the units place

Therefore, general form of a three-digit number abc is
100 $\times$ a + 10 $\times$ b + 1 $\times$ c

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Similar questions

In a cyclic quadrilateral ABCD,it is being given that $∠ A = (x + y + 10)^{\circ}, ∠ B = (y + 20)^{\circ}, ∠ C = (x + y - 30)^{\circ}, a n d ∠ D = (x + y)^{\circ}, T h e n ∠ B = ? (a) 70^{\circ} (b) 80^{\circ} (c) 100^{\circ} (d) 110^{\circ}$

The general form of a $\times$ 100 + b $\times$ 10 + c $\times$ 1 is ___

Q. The number of all 3-digit numbers abc (in base 10) for which

(a \times b \times c) + b (a + c) + (c \times a) + a + b + c = 29

A two digit number is given by 10a + b , then number obtained by reversing its digits is ___________

3 digit number abc is represented as 100a + 10b + c.

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General form of a three-digit number abc is

The correct option is B 100×a + 10×b + 1×c abc is a 3-digit number, where: • a is in the hundreds place • b is in the tens place • c is in the units place Therefore, general form of a three-digit number abc is 100×a + 10×b + 1×c

The correct option is B 100×a + 10×b + 1×c
abc is a 3-digit number, where:
• a is in the hundreds place
• b is in the tens place
• c is in the units place

Therefore, general form of a three-digit number abc is
100 $\times$ a + 10 $\times$ b + 1 $\times$ c