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Question

Geometrical isomerism is not shown by

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Solution

Conditions for Geometrical Isomerism:
1. Free rotation must be restricted
2. Both the terminals of the system must be attached with different atoms/groups.


Double bonds have restricted rotation so all given compound obeys condition (1).

In compound (a) and (b), both the terminals of the doubly bonded carbon are different. Hence, they shows geometrical isomerism.

In compound (c), one of the terminal doubly bonded carbon has same hydrogen groups. Hence, it does not show geometrical isomerism.



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