Question

gets warm up but if temperature of gas is lower than $T_i$ will cool down. What will happen to a gas if It is adiabatically expanded at ${50}^{0}C$ if its Boyle's temperature is ${20}^{0}C$

• A. heating
• B. cooling
• C. constant
• D. none of these

Answer 1

The correct option is B cooling

Boyle temperature, $T_b=\frac{a}{Rb}={20}^{0}C=293K$

inversion temperature , $T_i=\frac{2a}{Rb}={313}^{0}C=586K$

$\therefore {50}^{0}C<T_i$, on expansion cooling occurs.

Hence , option B is correct .