We know that f1: R → R, given by f1(x)=x, and f2(x)=-x are one-one.
Proving f1 is one-one:
So, f1 is one-one.
Proving f2 is one-one:
So, f2 is one-one.
Proving (f1 + f2) is not one-one:
Given:
(f1 + f2) (x) = f1 (x) + f2 (x)= x + (-x) =0
So, for every real number x, (f1 + f2) (x)=0
So, the image of ever number in the domain is same as 0.
Thus, (f1 + f2) is not one-one.